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4x^2-49^2=15
We move all terms to the left:
4x^2-49^2-(15)=0
determiningTheFunctionDomain 4x^2-15-49^2=0
We add all the numbers together, and all the variables
4x^2-2416=0
a = 4; b = 0; c = -2416;
Δ = b2-4ac
Δ = 02-4·4·(-2416)
Δ = 38656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38656}=\sqrt{256*151}=\sqrt{256}*\sqrt{151}=16\sqrt{151}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{151}}{2*4}=\frac{0-16\sqrt{151}}{8} =-\frac{16\sqrt{151}}{8} =-2\sqrt{151} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{151}}{2*4}=\frac{0+16\sqrt{151}}{8} =\frac{16\sqrt{151}}{8} =2\sqrt{151} $
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